Arithmetic Chapter 12 Measurement Of Time
Question 1. Add the following :
1. (8 hours 32 minutes 41 seconds) + (18 hours 42 minutes 25 seconds)
Solution:
Given:
(8 hours 32 minutes 41 seconds) + (18 hours 42 minutes 25 seconds)
Here for Sec:
41 + 25 = 66 seconds = 1 min. 6 sec.
(60 sec. = 1 min.)
For Min:
32 + 42 + 1 = 75 min.
= 1 hr. 15 min (60 Min. = 1 hr.)
For Hours:
8 + 18 + 1 = 27 hours.
Class 6 Math Solution WBBSE
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∴ The required sum = 27 hours 15 minutes 6 seconds
(8 hours 32 minutes 41 seconds) + (18 hours 42 minutes 25 seconds) = 27 hours 15 minutes 6 seconds
WBBSE Class 6 Measurement of Time Notes
2. (12 days 10 hours 42 minutes) + (25 days 14 hours 28 minutes) + (17 days 11 hours 32 minutes)
Solution:
Given:
(12 days 10 hours 42 minutes) + (25 days 14 hours 28 minutes) + (17 days 11 hours 32 minutes)
42 + 28 + 32 = 102 min.
= 1 hr. 42 min. (60 min. = 1 hr.)
For Hour:
1 + 10 + 14 + 11 = 36 hr.
= 1 day 12 hr.
(24 hr. = 1 day)
For Days:
(1 + 12 + 25 + 17) = 55 days.
Class 6 Math Solution WBBSE
∴ The required sum = 55 days 12 hours 42 minutes.
(12 days 10 hours 42 minutes) + (25 days 14 hours 28 minutes) + (17 days 11 hours 32 minutes) = 55 days 12 hours 42 minutes.
Understanding Time Measurement
3. (4 years 7 months 17 days) + (9 years 11 months 7 days) + (8 years 5 months 27 days)
Solution:
Given:
(4 years 7 months 17 days) + (9 years 11 months 7 days) + (8 years 5 months 27 days)
For Days:
17 + 7 + 27 = 51 days
= 1 month 21 days (30 days = 1 month)
For Mths:
1 + 7 + 11 + 5 = 24 mths.
= 2 yrs.
(12 Months = 1 year)
For Year:
(2+ 4 + 9 + 8 = 23 years.
∴ The required sum = 23 years 21 days.
(4 years 7 months 17 days) + (9 years 11 months 7 days) + (8 years 5 months 27 days) = 23 years 21 days.
Short Questions on Measurement of Time
Question 2. Subtract :
1. (6 hours 2 minutes 2 seconds) – (2 hours 55 minutes 42 seconds)
Solution:
Given:
(6 hours 2 minutes 2 seconds) – (2 hours 55 minutes 42 seconds)
1 min. = 60 sec.
∴ 60 + 2 = 62 sec.
62 – 42 = 20 secs
1 hr. = 60 min.
101 – 55 = 46 min.
5-2 = 3 hrs.
(6 hours 2 minutes 2 seconds) – (2 hours 55 minutes 42 seconds)= 3 hrs 46 min 20 secs
2. (11 years 2 months 16 days) – (5 years 10 months 21 days)
Solution:
Given:
(11 years 2 months 16 days) – (5 years 10 months 21 days)
1 month = 30 days
46 – 21 = 25 days
1 yr. = 12 months
13 – 10 = 3 months
10 – 5 = 5 yrs.
∴ The required value of subtraction = 5 years. 3months 25 days
(11 years 2 months 16 days) – (5 years 10 months 21 days) = 5 years. 3months 25 days
Practice Problems on Time Measurement
Question3. Multiply:
1. (7 hrs. 32 mins. 41 secs.) x 3
Solution:
Given:
(7 hrs. 32 mins. 41 secs.) And 3
1 min. = 60 secs.
1 hr = 60 min.
(7 hrs. 32 mins. 41 secs.) x 3
= 21 hrs. 96 mins. 123 secs.
= 21 hrs. (96 + 2) mins. (123 – 120 secs.) = 21 hrs. 98 mins. 3 secs.
= (21 + 1) hrs. (98 – 60) mins. 3 secs.
= 22 hrs. 38 mins. 3 secs.
∴ The required value of the product
= 22 hours 38 minutes 3 secs.
(7 hrs. 32 mins. 41 secs.) x 3 = 22 hours 38 minutes 3 secs.
2. (7 months 12 days 8 hrs.) x 12
Solution :
Given:
(7 months 12 days 8 hrs.) And 12
1 day = 24 hrs.
1 month = 30 days
1 year = 12 months
= (7 months 12 days 8 hours.) x 12
= 84 months 144 days 96 hours.
= 84 months (144 + 4) days 0 hours.
= 84 months 148 days = (84 + 4) months 28 days = 88 months 28 days = 7 yrs. 4 months 28 days.
∴ The required value of the product
= 7 years 4 months. 28 days.
(7 months 12 days 8 hrs.) x 12 = 7 years 4 months. 28 days.
Important Definitions Related to Time Measurement
Question 4. Divide:
1. (15 hrs.) ÷12
Solution:
Given:
(15 hrs.) And 12
1 hour = 60 minutes.
(15 hours) ÷ 12
= 15/12 hours.
= 5/4 hours.
= \(1 \frac{1}{4}\) hours
= 1 hour (\(\frac{1}{4}\) x 60 ) minutes.
= 1 hour. 15 minutes.
∴ The required quotient = 1 hour 15 minutes.
(15 hrs.) ÷12 = 1 hour 15 minutes.
2. (3 hrs. 27 mins.) ÷ 9
Solution:
Given:
(3 hrs. 27 mins.) And 9
∵ 1 hour. = 60 minutes.
Class 6 Math Solution WBBSE In English
= (3 hrs. 27 minutes) ÷ 9
= (3 x 60 + 27) minutes ÷ 9
= 207 minutes ÷ 9
= 23 minutes.
∴ The required quotient = 23 minutes.
Question 5. Your present age is 11 years 7 months 11 days. Any person can have the right to give a vote when the person is 18 years old. After how many years will you have to fight to give a vote?
Solution:
Given:
My present age is 11 years 7 months 11 days. Any person can have the right to give a vote when the person is 18 years old.
When you will be 18 years old, then will have the right to give a vote.
But your present age is 11 years 7 months 11 days.
1 month = 30 days
30 – 11 = 19 days
1 years = 12 months
11 – 7 = 4 months
17 – 11 = 6 years.
∴ After 6 years 4 months 19 days you will attain the age of 18 years, then only you will have the right to give a vote.
Examples of Real-Life Applications of Time Measurement
Question 6. Your father’s present age is 52 years 8 months 21 days. Your elder uncle’s age is 3 years 10 months 25 days more than your father’s. What is the present age of your elder uncle?
Solution:
Given:
My father’s present age is 52 years 8 months 21 days. My elder uncle’s age is 3 years 10 months 25 days more than My father’s.
1 month = 30 days
21 + 25 = 46 days
10 + 8 + 1 = 19 months
1 yr. = 12 months
∴ The present age of your elder uncle is 56 years and 7 months.
Question 7. Bablu’s date of birth is 19-11-1975. What was his age on 11–10-2000?
Solution :
Given:
Bablu’s date of birth is 19-11-1975.
1 month = 30 days
41 – 19 = 22 days
1 years = 12 months
21 – 11 = 10 months
1999 – 1975 = 24 yrs.
Bablu’s age on 11-10-2000 is 24 yrs 24 yrs 22 days
Question 8.
1. Write down the leap-years from 1895 year to the 1915 year
Solution:
The required leap years from 1895 year to the 1915 year are
1896, 1904, 1908, and 1912.
2. Write down the leap years from 2010 year to 2030 year.
Solution :
The required leap years from 2010 year to the 2030 year are
2012, 2016, 2020, 2024, 2028.
Conceptual Questions on Calculating Duration
Question 9. Write down all the leap years up to the year 2015 after the independence of India.
Solution: India was independent in 1947. The year 1947 is not a leap year.
The first leap year after the independence of India is 1948.
The required leap years are :
1948, 1952, 1956, 1960, 1964, 1968, 1972, 1976, 1980, 1984, 1988, 1992, 1996, 2000, 2004, 2008, 2012.
There are 17 leap years up to the year 1915 after the independence of India.
Question 10. If the 1st February of 2010 was Monday, what days were the 1st March and 1st April of 2010?
Solution: Total number of days after 1st February 2010 to 1st March 2010 (only one day of 1st February and 1st March 2010 is included) = 28 days.
(∵ The year 2010 is not a leap year)
Since the remainder is zero, the 1st of March 2010 was Monday.
Total number of days after 1st February 2010 to 1st April 2010 only one day of 1st February 2010 and 1st April 2010 is included
= 27 + 31 + 1
= 59 days.
Since the remainder is 3, the 3rd-day counting after Monday will be the required day and this is Thursday.
∴ 1st April 2010 was Thursday.
Real-Life Scenarios Involving Schedules and Timetables
Question 11. The present age of Jhilmil is 1/4 part of the present age of her father. The present age of her father is 53 years. What is the present age of Jhilmil?
Solution:
Given:
The present age of Jhilmil is 1/4 part of the present age of her father. The present age of her father is 53 years.
The present age of Jhilmil’s father = is 53 years.
∴ The present age of Jhilmil = (53 years) x 1/4 = (53 years + 4)
= (53 x 12 months) + 4
= (636 months) + 4
= 159 months
= 13 years 3 months.
∴ The present age of Jhilmil is 13 years and 3 months
1 year = 12 months
The present age of Jhilmil is 13 years and 3 months
Question 12. Shekhar Pal of our village can make 4 earthen images in 11 hours and 36 minutes. What will be the time taken by him to make 1 image if it is assumed that each image can be made in equal time?
Solution:
Given:
Shekhar Pal of our village can make 4 earthen images in 11 hours and 36 minutes.
The time taken by Shekhar Pal to make 1 image
= (11 hours 36 minutes ) + 4
= (11 x 60 + 36) minutes + 4
= 696 minutes + 4
= 174 minutes
= 2 hours 54 minutes.
∴ The required time = 2 hours 54 minutes.
1 hour = 60 minutes.
The required time = 2 hours 54 minutes