WBCHSE Class 11 Chemistry Notes For Hydrogen Peroxide

Hydrogen Peroxide And Its Preparation

Hydrogen peroxide (H2O2) is another hydride of oxygen. It was discovered by the French chemist Thenard in 1818. Unlike water, it is very unstable and so, it does not occur as such in nature. Hydrogen peroxide can be prepared by the following methods.

From Sodium Peroxide (Merck’s Process)

An aqueous solution of H2O2 may be prepared by the action of 20% dilute sulphuric acid, cooled to 0°C by freezing mixture, on a calculated amount of Na2O2.

Sodium sulfate produced in the reaction separates out as crystals of Glauber’s salt (Na2SO4.10H2O). The filtrate, when distilled under reduced pressure, produces a 30% H2O2 solution. This solution is known as Merck’s perhydrol.

⇒ \(\mathrm{Na}_2 \mathrm{O}_2+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{Na}_2 \mathrm{SO}_4+\mathrm{H}_2 \mathrm{O}_2\)

WBCHSE Class 11 Chemistry Notes For Hydrogen Peroxide

From Barium Peroxide (Laboratory Preparation)

Principle: The laboratory preparation of hydrogen peroxide involves reacting an ice-cold thin paste of hydrated barium peroxide (BaO2-8H2O) with an ice-cold solution of 20% H2SO4.

Hydrogen From barium peroxide

Procedure: In a beaker, a thin paste of hydrated barium peroxide is prepared by adding a small amount of water to it. In another beaker, 20% dilute H2SO4 is taken. Both the beakers are well-cooled by placing them in a freezing mixture.

  • Then the cold paste is slowly added to the cold acid solution, and kept in a freezing mixture, with constant stirring. The addition of paste is stopped when the mixture remains still slightly acidic.
  • As a result of the reaction between barium peroxide and dilute sulphuric acid, H2O2 is produced and white insoluble BaSO4 is precipitated. Solid BaSO4 is then separated by filtration when a dilute aqueous solution (5%) of H2O2 is obtained as the filtrate.

Limitations: Hydrogen peroxide prepared by this method contains appreciable amounts of Ba2+ ions (in the form of dissolved barium persulphate) which may catalyze the decomposition of H2O2. Therefore, H2O2 prepared by this method cannot be preserved for a long time.

  1. The reaction should be carried out at low temperatures because H2O2 is a very unstable compound that dissociates easily into H2O and O2 if the temperature is increased.
  2. Dilute H2SO4 instead of concentrated H2SO4 is to be used because H2O2 may decompose by the heat evolved when cone. H2SO4 reacts with BaO2.
  3. A thin paste of hydrated barium peroxide instead of anhydrous barium peroxide is to be used. This is because the heat generated by the addition of H2SO4 on anhydrous BaO2 decomposes H2O2 to H4O and O2.
    Moreover, if anhydrous Ba02 is used, an insoluble layer of BaSO4 is formed on it which prevents further reaction. However, there is no evolution of heat when a thin paste of BaO2 is used. Also, BaO2-8H2O exists as fine particles and this prevents the formation of insoluble BaSO4, and the reaction proceeds.
  4. The paste of BaO2 is poured into dilute H2SO4. If dilute H2SO4 is added to the paste, the concentration of BaO2 at the beginning of the reaction becomes sufficiently higher as compared to that of the acid. As a consequence, the mixture becomes basic in nature.
    In this basic medium, the decomposition of H2O2 becomes very fast. On the other hand, if the paste is poured into the ice-cold dilute acid, the mixture always contains an excess of the acid and this prevents the decomposition of H2O2.
  5. At the end of the reaction, the mixture should contain a small amount of surplus acid. This is because the excess acid acting as a negative catalyst decelerates the rate of decomposition of H2O2.
  6. In this process, neither HCl nor HNO3 can be used. HCl is not used because it reacts with BaOz to form water-soluble BaCl2 and the separation of H2O2 from the mixture becomes quite difficult HNO3 (an oxidizing agent) is not used as it oxidizes H2O2: H2O2 2HNO3→ 2H2O + 2NO2 + O2. Moreover, due to the formation of water-soluble Ba(NO3)2, the separation of H2O2 becomes difficult.
  7. It is better to use syrupy phosphoric acid instead of dilute sulphuric acid. This is because in the reaction of barium peroxide with dilute H2SO4, water-soluble barium persulphate (BaS208) is produced which decomposes H2O2. However, when syrupy phosphoric acid is used, the phosphate ions \(\left(\mathrm{PO}_4^{3-}\right)\) separate the heavy metal impurities like Pb2+ (which promotes the decomposition of H2O2) present in BaO2 as insoluble phosphates. Therefore, although both H2SO4 and H3PO4 slow down the dissociation of H2O2, it is better to use H3PO4.

The Reaction Of CO2 And Barium Peroxide

When a stream of CO2 is passed through a thin paste of barium peroxide in ice-cold water, H2O2 and BaCO3 are produced. The insoluble BaCO3 is separated by filtration when a dilute solution of H2O2 is obtained.

BaO2 + H2O + CO2→BaCOgl↓ + H2O2

Manufacture Of Hydrogen Peroxide

By the electrolysis of 50% H2SO4: H2O2 is manufactured by the electrolysis of 50% H2SO4 solution which is carried out at low temperature (-20°C) using platinum electrodes and a current of high density. Dihydrogen is liberated at the cathode and peroxodi sulphuric acid (H2S2O8) or Marshall’s acid is liberated at the anode.

⇒ \(2 \mathrm{H}_2 \mathrm{SO}_4 \rightleftharpoons 2 \mathrm{H}^{+}+2 \mathrm{HSO}_4^{-}\)

Cathode: \(2 \mathrm{H}^{+}+2 e \rightarrow 2[\mathrm{H}] \rightarrow \mathrm{H}_2\)

Anode: \( 2 \mathrm{HSO}_4^{-} \longrightarrow \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8+2 e\) peroxide sulphuric acid

Peroxodisulphuric acid is collected from the anode chamber and then distilled with water under reduced pressure, when it gets hydrolyzed. The low boiling H2O2 distills over along with water leaving behind the high boiling H2SO4 in the flask.

⇒ \(\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{H}_2 \mathrm{SO}_5+\mathrm{H}_2 \mathrm{SO}_4\)

⇒ \(\mathrm{H}_2 \mathrm{SO}_5+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{H}_2 \mathrm{SO}_4+\mathrm{H}_2 \mathrm{O}_2\)

Modification: A recent modification of the above method involves the use of an equimolar mixture of sulphuric acid and ammonium sulfate for electrolysis. Ammonium persulphate [(NH4)2S2O8] formed around the anode is collected and then distilled with water to form H2O2.

⇒ \(\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow 2 \mathrm{NH}_4 \mathrm{HSO}_4\)

⇒ \(\mathrm{NH}_4 \mathrm{HSO}_4 \rightleftharpoons \mathrm{NH}_4 \mathrm{SO}_4^{-}+\mathrm{H}^{+}\)

Cathode: \(2 \mathrm{NH}_4 \mathrm{SO}_4^{-}-2 e \rightarrow\left(\mathrm{NH}_4\right)_2 \mathrm{~S}_2 \mathrm{O}_8\)

Anode: 2\(\mathrm{NH}_4 \mathrm{SO}_4^{-}-2 e \rightarrow\left(\mathrm{NH}_4\right)_2 \mathrm{~S}_2 \mathrm{O}_8\)

⇒ \(\left(\mathrm{NH}_4\right)_2 \mathrm{~S}_2 \mathrm{O}_8+2 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{NH}_4 \mathrm{HSO}_4+\mathrm{H}_2 \mathrm{O}_2\)

Deuteroperoxide (D2O2) may be prepared by using K2SO4 instead of (NH4)2SO4 in the above process and distilling the resulting potassium persulphate with D2O.

⇒ \(\mathrm{K}_2 \mathrm{~S}_2 \mathrm{O}_8(s)+2 \mathrm{D}_2 \mathrm{O}(l) \rightarrow 2 \mathrm{KDSO}_4(a q)+\mathrm{D}_2 \mathrm{O}_2(l)\)

By auto-oxidation of 2-ethylanthraquinol: in this process, the air is passed through a 10% solution of 2-ethylanthraquinol in benzene and cyclohexanol when 2-ethylanthraquinol is oxidized by oxygen of air to 2-ethyl anthraquinone and oxygen is reduced to H2O2. The resulting H2O2 is separated from the organic layer by extraction with deionized water and the aqueous solution is distilled under reduced pressure to give a 30% (by weight) H2O2 solution.

2-ethyl-anthraquinone thus obtained is reduced with H2 in the presence of Pd catalyst to give back 2- ethylanthraquinol which is used again. Therefore, the raw materials required in this process are H2 and atmospheric oxygen which are inexpensive. Therefore, this modern industrial method of H2O2 preparation is the most convenient and economical.

Hydrogen By auto-oxidation of 2-ethylanthraquinol

By partial oxidation of 2-propanol:

⇒ \(\underset{\text { 2-propanol }}{\left(\mathrm{CH}_3\right)_2 \mathrm{CHOH}} \underset{\text { [under pressure] }}{\stackrel{\left(\text { little } \mathrm{H}_2 \mathrm{O}_2\right)+\mathrm{O}_2}{\longrightarrow}} \underset{\text { 2-propanone }}{\left(\mathrm{CH}_3\right)_2 \mathrm{C}=\mathrm{O}}+\mathrm{H}_2 \mathrm{O}_2\)

Preparation of H2O2 from Us dilute aqueous solution: Hydrogen peroxide produced by any of the above methods is in the form of a dilute solution. The solution is concentrated simply by heating it because H2O2 readily decomposes below its boiling point (2H2O2—>2H2O + O2). The dilute solution of H2O2 is concentrated carefully to get pure H2O2 by the following steps:

  1. The dilute solution of H2O2 is heated carefully in a water bath. Slow evaporation of water leads to the formation of a 50% H2O2 solution.
  2. The 50% solution thus obtained is placed in a vacuum desiccator over concentrated H2S04 when approximately 90% H2O2 solution is obtained.
  3. The 90% solution is distilled under reduced pressure (10-15 mm) when about 99% pure H2O2 is obtained.
  4. The 99% solution is finally cooled in a freezing mixture of solid CO2 and ether when crystals of H2O2 separate out. These are removed, dried, and remelted to yield very pure H2O2.

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