WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred

Arithmetic Chapter 4 Roman Number Up To One Hundred

Question 1. Write the following Roman Numbers in Hindu Arabic Numbers :

1. IV

2. VI

3. VII

4. VIII

5. IX

6. XI

7. XXVI

8. XXX

Read and Learn More WBBSE Solutions For Class 6 Maths

9. XXXIX

10. XXXVI

11. XL

12. XLI

13. XLIX

14. LV

15. LIX

16. LX

17. XC

18. XCV

19. XLV

20. LXXV

21. LXXX

22. XCVI

23. XCII

24. LXXIX

25. XCIX

Solution :

1. IV = 5 – 1

= 4;

2. VI = 5 + 1

= 6;

3. VU = 5 + 1 + 1

= 7;

4. VIII = 5 + 1 + 1 + 1

= 8 ;

5. IX = 101

= 9;

6. XI = 10 + 1

= 11 ;

7. XXVI = 10 + 10 + 5 + 1

= 26;

8. XXX = 10 + 10 + 10

= 30 ;

9. XXXIX = 10+ 10 + 10 + (10 – 1)

= 10 + 10 + 10 + 9

= 39 ;

10. XXXVI = 10 + 10 + 10 + 5 + 1

= 36 ;

11. XL = 50 – 10

= 40 ;

12. XLI = (50 – 10) + 1

= 41 ;

13. XLIX = (50 – 10) + (10 – 1)

= 40 + 9 = 49 ;

14. LV = 50 + 5

= 55;

15. LIX = 50 + (10 – 1)

= 50 + 9

= 59 ;

16. LX = 50 + 10

= 60 ;

17. XC = 100 – 10

= 90

18. XCV = (100 – 10) + 5

= 90 + 5

= 95

19. XLV = (50 – 10) + 5

= 40 + 5

= 45;

20. LXXV = 50 + 10 + 10 + 5

= 75 ;

 

21. LXXX = 50 + 10 + 10 + 10

= 80 ;

 

22. XCVI = (100 – 10) + 5 + 1

= 90 + 5 + 1

= 96 ;

23. XCII = (100 – 10) + 1 + 1

= 90 + 2

= 92 ;

24. LXXIX = 50 + 10 + 10 + (10 – 1)

= 70 + 9

= 79 ;

25. XCIX = (100 – 10) + (10 – 1)

= 90 + 9

= 99

 

Question 2. Write the following numbers in Roman Numbers:

1. 4

2. 7

3. 9

4. 14

5. 25

6. 31

7. 36

8. 44

9. 54

10. 65

11. 89

12. 90

13. 93

14. 98

Solution:

1. 4 = IV;

2. 7 = VII;

3. 9 = IX;

4. 14 = XIV;

5. 25 = XXV;

6. 31 = XXXI;

7. 36 = XXXVI;

8. 44 = XLIV;

9. 54 = LIV ;

10. 65 = LXV;

11. 89 = LXXXIX;

12. 90 = XC;

13. 93 = XCIII;

14. 98 = XCVIII;

 

Question 3. Choose the correct answer to the following:

 

WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 3.

 

Solution :

1. 40 = XL;

2. 49 = XLIX;

3. 84 = LXXXIV;

4. 90 = XC;

 

Question 4. Put <, =, > signs in the boxes given below :

1. 5 WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4. IV ;

2. 9 WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4. XI ;

3. XIV WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4. 14 ;

4. XIX WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4. XXI ;

5. 24 WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4. XXIV ;

6. LXXVI WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4. LXXIV.


Solution:

(i) 5 WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4.1. IV ;

(ii) 9  WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4.2. XI ;

(iii) XIV WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4.3. 14 ;

(iv) XIX WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4.2. XXI ;

(v) 24 WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4.3.XXIV ;

(vi) LXXVI WBBSE Solutions For Class 6 Maths Arithmetic Chapter 4 Roman Number Up To One Hundred Ex 4.1. LXXIV

 

Example 5. Write the following numbers in Roman Numbers :

1. 105,

2. 400,

3. 600,

4. 650,

5. 700,

6. 900,

7. 1513,

8. 2323.

Solution :

1. 105 = CV ;

2. 400 = CD ;

3. 600 = DC ;

4. 650 = DCL ;

5. 700 = DCC ;

6. 900 = CM ;

7. 1513 = MDXIII ;

8. 2323 = MMCCCXXHI.

 

Question 6. Write the following Roman Numbers in Hindu Arabic Numbers :

1. \(\overline{X C}\)

2. \(\overline{\mathbf{M}}\)

3. \(\overline{\mathbf{X X I V}}\)

4. \(\overline{C M}\)

Solution :

1. \(\overline{X C}\) = XC x 1000

= (100 – 10) x 1000

= 90 x 1000

= 90000;

2. \(\overline{\mathbf{M}}\)= M x 1000

= 1000 x 1000

= 1000000 ;

3. \(\overline{\mathbf{X X I V}}\) = (XXIV) x 1000

= [10 + 10 + (5 – 1)] x 1000

= (10 + 10 + 4) x 1000

= 24000 ;

4. \(\overline{C M}\) = CM x 1000

= (1000 – 100) x 1000

= 900 x 1000

= 900000.

 

Question 7. Write the following numbers in Roman Numbers :

(1) 44000 ; (2) 99000 ; (3) 660000 ; (4) 2336000

Solution : (1) 44000 = 44 x 1000 = XLIV x 1000 = \(\overline{\text { XLIV }}\) ;

(2) 99000 = 99 x 1000 = (XCIX) x 1000 = \(\overline{\text { XCIX }}\) ;

(3) 660000 = 660 x 1000 = (DCLX) x 1000 = DCLX \(\overline{\text { DCLX }}\) ;

(4) 2336000 = 2336 x 1000 = (MMCCCXXXVI) x 1000 = \((\overline{\mathrm{MMCCCXXXVI}})\)

 

Question 8. Express the results of addition and subtraction of the following into Hindu Arabic Numbers and Roman Numbers :

1. CDXXXIX + CCCLXXVI ;

2. \(\overline{\text { MCCXXV }}+\overline{\text { MMDCLXXXIII }}\) ;

3. DCCCLXXIX -DCCXXXIX ;

4. \(\text { MCCCXXII }-\overline{\text { MCCLXXXIV }}\)

Solution :

1. CDXXXIX + CCCLXXVI .

= [(500 – 100) + 10 + 10 + 10 + (10 – 1)] + [ 100 + 100 + 100 + 50 + 10 + 10 + 5 + 1]

= (400 + 30 + 9) + (375 + 1) = 439 + 376 = 815

The required sum = 815 (in Hindu Arabic Numbers)

= DCCCXV (in Roman Number)

2. \(\overline{\text { MCCXXV }}+\overline{\text { MMDCLXXXIII }}\)

= (MCCXXV) x 1000 + (MMDCLXXXIII) x 1000 (1000 + 100 + 100 + 10 + 10 + 5) x 1000 + (1000 + 1000 + 500 + 100 + 50 + 10 + 10 + 10 + 1 + 1 + 1) x 1000

= (1000 + 200 + 20 + 5) x 1000 + (2000 + 600 + 80 + 3) x 1000.

= 1225 x 1000 + 2683 x 1000

= 1225000 + 2683000

= 3908000

The required sum = 39080000 (in Hindu Arabic Number)

= MMMCMVIII (in Roman Number)

3. DCCCLXXIX – DCCXXXIX

= [500 + 100 + 100 + 100 + 50 + 10 + 10 + (10 – 1)] – [500 + 100 + 100 + 10 + 10 + 10 + (10 – 1)]

= [500 + 300 + 70 + 9] – [500 + 200 + 30 + 9]

= 879 – 739

= 140

∴ The required result of subtraction = 140 (in Hindu Arabic Number)

= CXL (in Roman Number)

4. \(\text { MCCCXXII }-\overline{\text { MCCLXXXIV }}\)

= (MCCCXXII) x 1000 – (MCCLXXXIV) x 1000

= (1000 + 100 + 100 + 100 + 10 + 10 + 1 + 1) x 1000

– [1000 + 100 + 100 + 50 + 10 + 10 + 10 + (5 – 1)] x 1000

= (1000 + 300 + 20 + 2) x 1000 – (1000 + 200 + 50 + 30 + 4) x 1000

= 1322 x 1000 – 1284 x 1000

= 1322000 – 1284000

= 38000

∴ The required result of subtraction = 38000 (in Hindu Arabic Number)

= \(\overline{\text { XXXVIII }}\) (in Roman Number)

 

Leave a Comment