## WBBSE Solutions For Class 6 Maths Algebra Chapter 3 Statistical Data Its Handling And Analysis

**Question 1. In class VI of Mitra Institution, classes have been held for 22 days in the month of June. The number of students attending classes on these 22 days are given below :**

**30, 28, 34, 29, 25, 30, 28, 26, 29, 30, 22, 25, 26, 29, 30, 31, 21, 27, 25, 13, ****32, 28.**

**Using the above raw data, prepare a frequency distribution table with tally marks.**

**Solution: **

**Arranging the given raw data in ascending order of magnitudes, we get: **

13, 21, 22, 25, 25, 25, 26, 26, 27, 28, 28, 28, 29, 29, 29, 30, 30, 30, 30, 31, 32, 34.

**Frequency Distribution Table of the number of students attending the classes in class VI of Mitra Institution in the month of June:**

**WBBSE Solutions For Class 6 Maths**

**Question 2. The weight (in kg) of 30 students of class VI of Saraswati Vidyamandir is given below :**

**32, 32, 37, 34, 37, 35, 35, 36, 37, 39, 40, 36, 37, 36, 32, 33, 31, 36, 37, 38, 40, 34, 36, 34, 35, 33, 34, 35, 32, 35.**

**Arranging these raw data, prepare a frequency distribution table.**

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**Solution:****Arranging the given raw data, in ascending order of magnitudes, we get:**

31, 32, 32, 32, 32, 33, 33, 34, 34, 34, 34, 35, 35, 35, 35, 35, 36, 36, 36, 36, 36, 37, 37, 37, 37, 37, 38, 39, 40, 40.

**Frequency Distribution Table of the weights (kg) of 30 students of class VI of Sar&swati Vidyamandir:**

**Question 3. A survey has been conducted of over 150 students of Habra High School. The content of the survey is how many students like to study what subject. The raw data obtained from the survey is given below:**

**Taking 1 unit = 5 students, prepare a Bar diagram. **

**Solution:** 1 unit = 5 students

25 students = 25/5 = 5 units

30 students = 30/5 = 6 units

40 students = 40/5 = 8 units.

**Frequency Distribution Table:**

**Class 6 Math Solution WBBSE**

**Scale:**

**Along X-axis:**

1 unit = 1 subject

(1 small square division)

**Along Y-axis:**

1 unit = 1 small square division

= 5 students

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**Question 4. The following is the raw data obtained from 20 famous mathematicians coming from different countries of the world who like to eat what types of fruits.**

**Taking 1 unit = 2 Mathematicians, prepare a Horizontal Bar Diagram based on this data. **

**Solution:**

∵ 2 Mathematicians = 1 unit

∴ 4 Mathematicians = \(\frac{1}{2} \times 4\)

6 Mathematicians = \(\frac{1}{2} \times 6\)

**Frequency Distribution Table:**

**Class 6 Math Solutions WBBSE English Medium**

**Question 5. The following is the bar diagram showing the number of students appearing at the Madhyamik Examination each year during the last 5 years of a school:**

**From the above bar diagram answer the following questions:**

**1. In which year maximum number of students have appeared for the examination?**

**Solution: **

The length of the bar diagram in the year 2012 has the greatest of all. So the maximum number of students appeared at the examination in the year 2012. This year 120 students have appeared for the examination.

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**2. In which year least number of students have appeared at the examination?****Solution:**

The length of the bar diagram in the year 2010 has the least of all.

So the least number of students appeared at the examination in the year 2010.

In this year 80 students appeared at the examination in the year 2010.

**3. How many more students appeared at the examination in the year 2011 than in the year 2010?**

**Solution:**

From the bar diagram, we see that 80 students appeared at the examination in the year 2010 and 110 students appeared at the examination in the year 2011.

110 – 80 = 30 more students have appeared at the examination in the year. 2011 than the year 2010.

**4. How many fewer students appeared for the examination in the year 2010 than the year 2009?**

**Solution:**

From the bar diagram, we see that 90 students appeared in the examination in the year 2009 and 80 students appeared at the examination.

90 – 80 = 10 fewer students appeared at the examination in the year 2009 than in the year 2010.

**5. How many total students appeared at the examination between 2008 and 2010 both years included?**

From the diagram, we set that, 100 students appeared in the examination in the year 2008.

90 students appeared in the examination in the year 2009.

80 students appeared at the examination in the year 2010.

From the year 2008 to the year 2010, a total number of students have appeared at the examination

= 100 + 90 + 80

= 270 students.