WBBSE Solutions For Class 6 Maths Algebra Chapter 1 Concept Of Algebraic Variables Or Quantities Or Symbols

Algebra Chapter 1 Concept Of Algebraic Variables Or Quantities Or Symbols

Question 1. Write in words the following quantities:

1. 10a

Solution:

10a means that the variable a is multiplied by 10.

2. a + c

Solution:

a + c means that a is added to c or the addition of a and c.

3. x – y 

Solution:

x – y means that the value of y is subtracted from the value of x.

Class 6 Math Solutions WBBSE English Medium

4. 9x + 2

Solution:

9x + 2 means that 2 is added to the value of 9 times of x.

WBBSE Class 6 Algebraic Variables Notes

5. 3x – 7

Solution:

3x – 7 means that 7 is subtracted from the value of 3 times of x.

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6. (p/3) – 4

Solution:

(p/3) – 4 means that 4 is subtracted from the quotient p/3

i.e., 4 is subtracted from the value of p divided by 3.

7. x > y

Solution:

x > 6 means that x is greater than 6.

8. p >≠ 9.

Solution :

p >≠ 9 means that p is not greater than 9.

Understanding Algebraic Symbols

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Question 2. Express the following statements in algebraical quantities by sign and symbols :

1. The addition of x and 7.

Solution:

x + 7.

2. Subtraction of 9 from y 

Solution:

y – 9.

3. Multiplication of a by 3.

Solution:

3a.

4. x is greater than 13.

Solution:

x > 13.

5. Division of x by 8.

Solution:

x/8.

6. y is not equal to 5.

Solution:

y ≠ 5.

7. The addition of 7 to 10 times p.

Solution:

10p + 7.

8. Subtraction of 1 from the multiplication of x by 3.

Solution:

3x – 1.

Short Questions on Algebraic Variables

9. x is less than y.

Solution:

x < y.

10. b is not less than 8.

Solution:

b <≠ 8.

 

Question 3.

1. The present age of Suvadra is x years, after 4 years her age will be years.

Solution:

Given: 

The present age of Suvadra is x years, after 4 years her age will be years

x + 4

2. The present age of Avisekh is y years, 7 years before his age was years.

Solution:

Given:

The present age of Avisekh is y years, 7 years before his age was years.

y – 7

3. There are x rose flower plants in the garden of Kamala. There are rose flower plants in the garden of Kamalini 1/4 the that in the garden of Kamala. So the number of rose flower plants in the garden of Kamalini is.

Common Questions About Algebraic Expressions

Solution:

Given:

There are x rose flower plants in the garden of Kamala. There are rose flower plants in the garden of Kamalini 1/4 the that in the garden of Kamala. So the number of rose flower plants in the garden of Kamalini is.

x/4

4. Shibu has given a subscription of Rs x for Durgapuja at Muktipara of Bamangachi. Manish has given a subscription of Rs 10 more than twice what Shibu has given. So Manish has given Rs. as a subscription for Durgapuja.

Solution:

Given:

Shibu has given a subscription of Rs x for Durgapuja at Muktipara of Bamangachi. Manish has given a subscription of Rs 10 more than twice what Shibu has given. So Manish has given Rs. as a subscription for Durgapuja.

2x + 10

5. The height of Himangshu is 3 less than that of Hindal. If the height of Hindal is x cm, then the height of Himangshu is cm.

Solution:

Given:

The height of Himangshu is 3 less than that of Hindal. If the height of Hindal is x cm, then the height of Himangshu is cm.

x – 3.

Practice Problems on Algebraic Quantities

Question 4. Express the following statements algebraically using symbols and operation signs:

1. The height of Kankana is y The height of Kumudini is 21 cm less than that of Kankana. What is the height of Kumudini?

Solution:

Given:

The height of Kankana is y The height of Kumudini is 21 cm less than that of Kankana.

The height of Kumudini = (y – 21) cm.

2. The present age of the father is 5 times that of his son. The present age of the son is x What is the present age of the father?

Solution:

Given:

The present age of the father is 5 times that of his son. The present age of the son is x

The present age of the father = 5x years

Conceptual Questions on Properties of Algebraic Operations

3. Anindita has pnote books. Sunanda has notebooks 1/4th that of Anindita. How many notebooks have Sunanda?

Solution:

Given:

Anindita has pnote books. Sunanda has notebooks 1/4th that of Anindita.

Sunanda has p/4 notebooks.

4. Mihir takes x hours to go from his house to school. Mitali takes 5 hours less than 3 times that Mihir takes to go from house to school. How many hours does Mitali take to go from her house to school?

Solution:

Given:

Mihir takes x hours to go from his house to school. Mitali takes 5 hours less than 3 times that Mihir takes to go from house to school.

Mitali takes (3x – 5) hours to go from her house to school.

Real-Life Scenarios Involving Problem Solving with Variables

Question 5.

1. Your present age is 4 years less than that of your elder brother. If the present age of your elder brother is x years, then what is your present age?

Solution:

Given:

Your present age is 4 years less than that of your elder brother. If the present age of your elder brother is x years,

Your present age is (x – 4) years.

2. Thirtha has caught x Partha has caught 5 fishes more than that Thirtha. How many fishes have been caught by Partha?

Solution :

Given:

Thirtha has caught x Partha has caught 5 fishes more than that Thirtha.

Partha has caught (x+ 5) fish.

 

Question 6.

1. My father has brought x packets of sweets today. Each packet contains 5 sweets. How many sweets have been brought my father?

Solution:

Given:

My father has brought x packets of sweets today. Each packet contains 5 sweets.

Father has brought x packets of sweets. Each packet contains 5 sweets.

So x packets of sweets contain 5x sweets.

My father brought today 5x sweets.

2. Today Pradip has worked out sums 2 less than 4 times that Prabir has worked out. Prabir has worked out x sums today. How many sums Pradip has worked out today?

Solution :

Given:

Today Pradip has worked out sums 2 less than 4 times that Prabir has worked out. Prabir has worked out x sums today.

Prabir has worked out sums today = x.

Pradip has worked out today = (4x – 2) sums.

 

Question 7.

1. The length of each side of a square is “a” meter, then what is the perimeter of the square?

Solution:

Given:

The length of each side of a square is “a” meter,

We know that the length of each side of the square is the same and the number of sides of the square = 4.

The length of each side = meters (given)

The perimeter of the square = 4 x a meters

= 4a meters.


2. The length and breadth of a rectangle are
x cm, and y cm respectively. What is the perimeter of the rectangle?

Solution :

Given:

The length and breadth of a rectangle are x cm, and y cm respectively.

The length of the given rectangle = x cm

and the breadth of the rectangle = y cm

∴ The perimeter of the rectangle = 2 (length + Breadth)

= 2 (x + y) cm.

Examples of Real-Life Applications of Algebraic Variables

Question 8. Moumita and Madhumita have purchased some birds of different designs and different colors from a fair in their locality. Moumita has purchased n birds and Madhumita has purchased birds 8 more than 1/4th part that Moumita has purchased. How many birds have been purchased by Madhumita ?

Solution:

Given:

Moumita and Madhumita have purchased some birds of different designs and different colors from a fair in their locality. Moumita has purchased n birds and Madhumita has purchased birds 8 more than 1/4th part that Moumita has purchased.

Moumita has purchased = n birds

Madhumita has purchased = 8 birds more than 1/4th part that Moumita has

purchased = \(\left(8+\frac{1}{4} \times n\right)\) birds.

= \(\left(8+\frac{n}{4}\right)\) birds.

 

 

 

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