Logic Gates
Question 1. The logic gate represented in the adjoining figure is
- An OR gate
- A NOT gate
- A NAND gate
- An XOR gate
Answer: 1. An OR gate
The output of the combination of the two given gates represents an OR gate.
G1 is a NOR gate, which gives the output \(Y^{\prime}=\overline{A+B}\).
Two identical inputs in a NOR gate give the same output as a NOT gate.
Thus, \(\bar{Y}=\overline{Y^{\prime}}=\overline{\overline{A+B}}\) = A + B.
Hence, it is an OR gate.
The truth table for this gate is as under.
This output corresponds to an OR gate.
Question 2. The given combination of gates is equivalent to
- An AND gate
- An OR gate
- A NOR gate
- A NOT gate
Answer: 3. A NOR gate
The output of the combination of the given gates (G1 and G2) with a NOT gate is the same as that of a NOR gate.
The output of G1 (a NOR gate) is \(Y^{\prime}=\overline{A+B}\).
The G2 gate is equivalent to a NOT gate.
Hence, \(Y^{\prime \prime}=\overline{Y^{\prime}}=\overline{\overline{A+B}}\) = A + B.
Finally, through a NOT gate, \(Y=\overline{A+B}\), which is the output of a NOR gate. This is also indicated by the following truth table.
The output corresponds to that of a NOR gate.
Question 3. Which logic gate is represented by the given combination of logic gates?
- OR
- NAND
- AND
- NOR
Answer: 3. AND
The truth table for the given combination of gates is shown below. In the given circuit, there are two NOT gates whose outputs Y1 and Y2 are complements of A and B. These inputs to the given NOR gate give the final output Y as that of an AND gate.
The truth table shows that when both the inputs are high then only we are getting a high value of the output, otherwise zero. This corresponds to an AND gate.
Question 4. The output in the given circuit is
- (A + B).\(\bar{B}\)
- (A.B).\(\bar{B}\)
- (A + B).B
- (A.B) + B
Answer: 1. (A + B).\(\bar{B}\)
The output Y’ of the OR gate. G1 is Y’ = A + B and the output of G2 is \(\bar{B}\). G3 is an AND gate whose output is
\(Y=Y^{\prime} \cdot B=(A+B) \cdot \bar{B}\)Question 5. The symbolic representations of four logic gates are shown below.
Pick out the combination that represents the symbols for the AND, NAND, and NOT gates respectively.
- (3), (2), and (1)
- (2), (4), and (3)
- (3), (2), and (4)
- (2), (3), and (4)
Answer: 3. (3), (2), and (4)
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The symbols given in the question are for the
- OR,
- AND,
- NOT and
- NAND gates
“logic gates questions with answers “
Question 6. The circuit given here is equivalent to
- An AND gate
- A NAND gate
- A NOR gate
- A OR gate
Answer: 3. A NOR gate
The output of the (NOR gate) G1 is \(Y^{\prime}=\overline{A+B}\)
The output of the (NAND gate) G2 is Y” = \(Y^{\prime \prime}=\overline{Y^{\prime}}=\overline{A+B}=A+B\)
The output of the (NOT gate) G3 is Y = Y” = A + B.
This final output corresponds to a NOR gate, which is confirmed by the truth table given below.
Question 7. To get an output of 1 for the following circuit, the correct choice for the inputs is
- A = 1, B = 0, C = 0
- A = 1, B = 1, C = 0
- A = 1, B = 0, C = 1
- A = 0, B = 1, C = 0
Answer: 3. A = 1, B = 0, C = 1
The output of G1 (an OR gate) is Y’ = A + B.
The output Y of G2 (an AND gate) is Y = (A + B).C
For Y =1, we have C = 1, and either A = 0 and B =1 or A =1 and B = 0 or A = 1 and B = 1.
Hence, option (3) gives a correct combination.
Question 8. What are the respective values of the output Y in the given circuit when all three inputs (A, B, C) are first 0 and then 1?
- 0 and 1
- 0 and 0
- 1 and 0
- 1 and 1
Answer: 3. 1 and 0
The output of the AND gate G1 is Y’ = A.B
The output of the NAND gate G2 is \(Y=\overline{Y^{\prime} \cdot C}=\overline{(A \cdot B) \cdot C}\)
If A = B = C = 0 then Y = \(\bar{0}\) = 1.
If A = B = C =1 then Y = \(\bar{1}\) = 0.
This can be shown by the truth table given below.
Question 9. The output Y in the logic circuit shown in the figure will be
- \(Y=\bar{A} \cdot \bar{B}\)
- \(Y=\overline{A \cdot B}\)
- Y = A.B
- Y = \(Y=\overline{A+B}\)
Answer: 3. Y = A.B
In the given circuit, G1 is a NAND gate and G2 acts as a NOT gate.
⇒ \(Y^{\prime}=\overline{A \cdot B}\)
and \(Y=\overline{Y^{\prime}}=\overline{\overline{A \cdot B}}=A \cdot B\) → (1)
Now, (1) is the Boolean expression for an AND gate.
Question 10. In the given circuit, the values of the output Y for all possible inputs A and B are expressed by the truth table
Answer: 4.
In the given diagram, G1 represents a NOR gate and G2 is effectively NOT gate.
The output of G1 is \(Y^{\prime}=\overline{A+B}\) and the final output is \(Y=\overline{Y^{\prime}}=\overline{\overline{A+B}}=A+B\) which represents the Boolean expression for an OR gate. The truth table is given below.
This corresponds to the option (4).
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Question 11. The diagram shown in the adjoining figure performs the logic operation of a/an
- OR gate
- AND gate
- XOR gate
- NAND gate
Answer: 2. AND gate
Gx is a NAND gate whose output is \(Y^{\prime}=\overline{A \cdot B}\).
A NAND gate with one input is equivalent to a NOT gate. Thus, the final output is \(Y=\overline{Y^{\prime}}=\overline{\overline{A \cdot B}}\) = A.B, which is the Boolean expression for an AND gate.
Thus, the given combination of gates performs the logic operation of an AND gate.
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Question 12. Which of the following gates will have an output of 1?
- 1
- 2
- 3
- 4
Answer: 2. 2
- Is a NAND gate with the output Y = \(\overline{1 \cdot 1}=\overline{1}\) = 0.
- Is a NAND gate with the output Y = \(\overline{0 \cdot 1}=\overline{0}\) = 1.
- Is a NOR gate with the output Y = \(\overline{1+1}=\overline{1}\) = 0.
- Is an XOR gate with the output Y = 0.
Thus, only (2) will give an output of 1.
Question 13. The given figure shows a logic operation with two inputs A and B and the output C. The voltage waveforms across A, B, and C are as given. The logic circuit represents a/an
- NOR gate
- AND gate
- OR gate
- NAND gate
Answer: 3. OR gate
The values of the inputs A and B and the output C as given in waveforms are shown in the following table.
The values of the output C indicate that the logic circuit represents an OR gate.
Question 14. The adjoining figure shows a logic circuit with two inputs A and B and the output Y. The voltage waveforms of A, B, and Y are given in the figure. The logic circuit represents
- A NOR gate
- An OR gate
- A NAND gate
- An AND gate
Answer: 3. A NAND gate
The values of the inputs A and B and the output Y at different time intervals are shown in the following table.
The values of the output Y indicates that the. logic operation is of a NAND gate.
Question 15. The figure given here shows a logic circuit with two inputs A and B and the output C. The voltage waveforms of A, B, and C are shown in the figure. The logic circuit is for a/an
- AND gate
- NAND gate
- OR gate
- NOR gate
Answer: 1. AND gate
The values of the inputs A and B and the output C at different time intervals are shown below in a tabular form.
The values of the output C correspond to the logic operation of an AND gate.
Question 16. The correct Boolean operation represented by the circuit diagram shown is
- AND
- OR
- NAND
- NOR
Answer: 3. NAND
According to the given logic circuit, the LED will glow when both A and B are OFF (A = B = 0) or when either A or B is OFF.
The LED will not glow when it is short-circuited by closing both A and B (A = B = 1).
This is expressed in the following truth table, which gives the Boolean expression \(Y=\overline{A \cdot B}\) corresponding to a NAND gate.
Question 17. The truth table for the circuit given in the adjoining figure is
“logic gate questions and answers “
Answer: 2.
Let Y1 be the output of the given OR gate. With Y1 and A as the inputs in the NAND gate, the circuit produces the final output Y as shown in the following truth table.
Question 18. To get an output of 1 at R in the given logic circuit, the input values must be
- X = 0 and Y = 0
- X = 1 and Y = 0
- X = 1 and Y = 1
- X = 0 and Y = 1
Answer: 2.
The given logic circuit can be redrawn as shown in the given figure. The final output R is obtained as given in the truth table shown below.
Thus, to get an output of 1 at R, the values of the inputs must be X =1 and y = 0.
Question 19. The output of the given combination of logic gates is
- \(A \cdot \bar{B}\)
- \(\bar{A} \cdot B\)
- A.B + \(\overline{A \cdot B}\)
- \(A \cdot \bar{B}+\bar{A} \cdot B\)
Answer: 1. \(A \cdot \bar{B}\)
The logic circuit has been redrawn as shown here. The corresponding truth table is shown below.
This output Y is the same as that produced by the \(A \cdot \bar{B}\) gate shown below.
Hence, the given circuit corresponds to the Boolean expression \(Y=A \cdot \bar{B}\).
Question 20. The given logic circuit is equivalent to a/an
- AND gate
- NOR gate
- NANDgate
- OR gate
Answer: 4. OR gate
The truth table for the given logic circuit is shown below.
The output Y corresponds to an OR gate. Thus, the given logic circuit represents an OR gate.
Note: Y = \(\bar{A} \cdot \bar{B}\) = A + B
“logic gate questions and answers “
Question 21. The output of the given combination of gates is equivalent to a/an
- AND gate
- OR gate
- NOR gate
- NAND gate
Answer: 1. AND gate
The symbol acts as a NOT gate.
Hence, the Boolean expression for the output will be
∴\(\overline{(\overline{A+A})+(\overline{B+B})+(\overline{C+C})}=\overline{\bar{A}+\bar{B}+\bar{C}}=A \cdot B \cdot C\)
Hence, the given combination of gates is equivalent to an AND gate.
Question 22. The figure given below shows a logic circuit with two input signals A and B.
The output signal y is given by the graph
Answer: 3.
For the given logic gate, Y = \(\overline{\bar{A} \cdot \bar{B}}\) = A + B.
The truth table and the corresponding output are given below. The circuit is equivalent to an OR gate.
“logic gate questions and answers “
Question 23. For the given logic circuit, the truth table is
Answer: 4.
The output Y for the given logic circuit corresponds to an AND gate, whose truth table is given in option (4). This can be seen in the following table.